The MI28NM problem

the laser seems to have a max output of 250W
image

with that and the inverse square law you can calculate how much power the laser loses over distance

and that is ignoring atmospheric conditions

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again you showed an image that would indicate CIRCM can get ~50% of its energy on target at ~95 degrees gimble

and in a lot of that direct front/back band it could get both emiters onto a target so it probably is roughly the same effectiveness

Sphere was the wrong word, I should have said flat spheroid but yeah, that answers my question. It rotates 360°, then the little block on which the eye itself is mounted can rotate +/- 90° on the other axis to provide the necessary gimbal to counter the threat.

So as long as the eye can see 1 more degree than the block on which it is mounted, a 360° sphere is correct for it.

that would be 100W to 125W

ignoring power loss due to the Inverse square law and atmospheric conditions

also only having half of the laser beam will make it scatter

youre ignoring reflection capability of the turret
you cant really go over 90 and still expect the laser to go outwards rather than inwards

no it isnt

DIRCM range apparently:

I don’t see the problem if they overlap at 150m

simplified explanation:

cube is the emitter, plane is the reflector (turret)
image

at perfect 45
image

any more and the system can start burning its own body by reflecting the laser into itself

it might look reflective but it almost definitely is not reflective in the IR spectrum on which the laser operates

way over exaggerated here, because at the range these engage it would be fractions of a degree incidence angle

so if it isnt reflective, how is it able to steer the Laser in the first place

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i dont think you understand
the laser is reflected from the turrets into the incoming missile seeker

its the maximum limits of the CIRCM that can be calculated

the LAIRCM is another story but even that has limits

and? how is that the limit here

because the reflector would just need to have a limit of slightly over 45 degrees to cover that angle range

how would it start burning itself when the laser is still being reflected out through the dome, which we can tell it could be due to the pivot for the reflector being well past the edge of the dome

because this

image

the turret boundary itself would start burning if the reflector rotated further

the pivot should be ~twice as far past the boundary than you depicted it as

and you are overestimating the strength of these lasers, they absolutly would no be able to significantly damage the metal part of the housing in their average engagement time of the system

Wouldn’t pushing the reflector a few cm up solve the problem right away?

it would, and as you can see by the images it is further out than he depicted

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it would and it does on the LAIRCM by northrop grumman, but the CIRCM is an embedded design, hence why it is in this restriction

refer to this

image

CIRCM directors are embedded into the gimball assembly
a full 90 is not possible

also see here

image

@Alpharius11348

Okay, I understand now why you said 90°. Originally thought the thing was a direct laser, not a reflective one. Then yeah, your reworked bubble seems accurate. I stand corrected. Nice discussion, thanks.

i thought so too, but then i read saw the official brochure displaying the tracker (turret) and Laser (emitter) seperately

image