18.6 = (0.9925 * 19.07) + (0.0075 * x), where x is the density of our mysterious non-du elements.
Solving for x you get -43.6. So the non-DU parts of the L27A1 have negative density/mass. Note these are using the absolute minimum values from that source. Instead of the 99.42% DU they actually observe. Seems legit.
It’s pretty basis maths, so you should try doing it yourself instead of putting numbers blindly into a “black box calculator”. 18.96 is the final projectile density I get.
Edit:
Apparently this is the wrong formula for density. I used a weighted average of the densities.
That’s not the formula for density of an alloy though…
The correct formula is:
Which using your numbers looks like this:
And solves to x = 4.36
If you use 19.0 as the density for Depleted Uranium it solves to x = 4.9
And if you use 19.05 it solves to x = 4.5, which just so happens to be the density of titanium.