28,000 * sqrt(3)/2
Tell me anyways
I believe we all know that basic trigonometric functions don’t apply to the Harrier for it is above such mortal human invented constraints. In fact, the entire mathematical field of study should be reformed to adhere to the likes of the Harrier, not the other way around.
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In all honesty i don’t know what you are asking. What do you mean by “standard force”?
The images you have shown shows 20k lb of force.
his engine would not be making the same in order for 14,000 to be 50% and an unknown amount to be the other .866
its not unknown
it is 14,000 * sqrt(3)
and its not as he said he was using 28,000 lbf
24,248.7
there, you figured it out
it only took other people telling you what it is
Look at my madskillz
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What number he used as basis doesn’t matter AT ALL for the argument if his math is correct or not. If the number in is wrong then that is easy to correct if the math is applied correctly.
I don’t care about the thrust values of the aircraft, i don’t care about which values are correct. What i do immensely care about is using math the correct way and not spreading misinformation about how to calculate things.
You are using the “half” wrong in this situation because you cannot just add them together for a total. Half does not mean that the other part is just as big, it JUST means half of the initial value, it doesn’t remove one half and leave the other half behind because the math doesn’t work that way with vectoring.
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Yes that example had a vertical thrust component of 24,00 and a horizontal one of 14,000
the goat organic chem tutor
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and if you do the math to take the magnitude of total thrust you will get 28,000 lbf
Never thought I’d see basic and objective mathematics become a point of contestation on the War Thunder forums but never say never huh
Yes
so what do you not understand
that is the absolute most basic example of vector math
Ah, the drawing they used when designing the F-35 :P
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