this is using force
No, it isn’t. Please answer what i asked.
what is thrust?
if not a force
In feetpics assessment he used a total gross thrust of 28,000 used the COS(60 degrees) and got 14,000
sqrt(14,000^2+14,000^2) = 19,798.98
he then used half of 28,000 to calculated the Harriers horizontal thrust loading.
he came up with a .81 TWR pushing the plane forwards
The FeetPics conspiracy to keep the Harrier dog shit goes all the way to the top.
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Why are you using 14,000 for the other component? no one has said to do that.
please answer the question exactly as i asked it.
if you want the other component you need the tan not the cos
its COS(60) + TAN(60)
runs so deep even the guys who built the harrier are in on it
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Nope, you did your own. you added a number he didn’t say.
being what number then hmm
20k lbs
I don’t know, you tell me, i don’t know where you got that from because no one has said that other number. You assumed that the other vector would be the same size, no one has said this.
.866
Basic first thing in trig. they are not linear.
around .85
ok so then what would the standard force be for this engine
20k lbs
It is still a vector and it dosent become longer
Doesn’t matter for the thing i’m trying to discuss with you. It can be whatever you want for the sake of discussion. But if we are looking at the image you have been showing then it’s 20k total for every angle.