runs so deep even the guys who built the harrier are in on it
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Nope, you did your own. you added a number he didn’t say.
being what number then hmm
20k lbs
I don’t know, you tell me, i don’t know where you got that from because no one has said that other number. You assumed that the other vector would be the same size, no one has said this.
.866
Basic first thing in trig. they are not linear.
around .85
ok so then what would the standard force be for this engine
20k lbs
It is still a vector and it dosent become longer
Doesn’t matter for the thing i’m trying to discuss with you. It can be whatever you want for the sake of discussion. But if we are looking at the image you have been showing then it’s 20k total for every angle.
28,000 * sqrt(3)/2
Tell me anyways
I believe we all know that basic trigonometric functions don’t apply to the Harrier for it is above such mortal human invented constraints. In fact, the entire mathematical field of study should be reformed to adhere to the likes of the Harrier, not the other way around.
4 Likes
In all honesty i don’t know what you are asking. What do you mean by “standard force”?
The images you have shown shows 20k lb of force.
his engine would not be making the same in order for 14,000 to be 50% and an unknown amount to be the other .866
its not unknown
it is 14,000 * sqrt(3)
and its not as he said he was using 28,000 lbf
24,248.7