“I don’t care about colors, i just want to know if the wall is green or red”
You can’t have one without the other.
Nope, he didn’t, he said the the horizontal part would be half of that 28k. YOU are adding that that must mean equal distribution when it does not mean that at all. It means that the lifting part will be even larger than that. You are comparing to a number that doesn’t exist.
In this instance you do
50% of the overall NET (acceleration) thrust at 60 degrees of nozzle is not being pushed backwards and that is that
The nozzles 60 degrees downwards are going to impart more power down then backwards for more upwards acceleration.
so what percentage is 10k of 20k then?
Would be funny to see you as a harrier pilot put the nozzles to 60 degrees expecting to go as fast forward as you are upwards.
It is though.
Because the “NET” you are talking about doesn’t exist. it’s an imaginary number that can’t be calculated against. The “input” and “NET” have the same value. it’s the same number with the same size.
read above that’s you as a harrier pilot
No, because what i’m saying doesn’t result in that.
This is a great example, the total IS NOT 17,300+10,000=27,300 . This is WRONG and cannot be calculated this way. you cannot a+b two vectors.
The total is sqrt(17,300^2 + 10,000^2) = 20,000
one component is 50% and the other is 86.6% of the total
whatever you say feetpics fan
No response to the rest? Just a haymaker?
just calculate it yourself what angle (α) do you need that the horizontal component equals half (10k lbs) of the hypothenuse (20k lbs)
that way you can prove that 45° is the right awnser
Just never fly a harrier and youll be fine. Or you’ll be accelerated straight up off the ground and crash.
Okay then, do the math yourself and prove it.
You have 20k force in. At what angle does one of the components become half of that, i.e 10k? and what does the other component become?
;)
Afraid to be proven wrong? Come on, do the math, see what happens :)
Or better yet, take it to an expert and see what they say.
To achieve equal parts force and acceleration up and forwards 45 degrees of nozzle angle is needed.
No need for math, experts did it for me.
so you dont want to do the math?
either you cant or you dont want to for some reason
just show us how right you are by doing the math
that way you can easily settle this by proving everyone wrong
omg this thread reminds me of the time learning vector addition, like head to tail method, tail to tail, components method, trig method, etc back in physics 11. takes me back
Not what i asked.
That is what is needing to be solved
and the math expers say that at 60° that the thrust has 50% a horizontal component of the thrust at 0°
