BAe Sea Harrier - Technical data and discussion

your own doc dissagrees with you

at a 45° angle you get more than 20000 lbs of force

whats 70% of 20k lbs?

~14000 lbs

you notice how it never equals 20k lbs of force unless the nozzel is at eithe 0° or 90°

In game all it does is impart some of the Net thrust downwards

Marketing lies the harrier cannot produce 1-1.5 times its wait in thrust according to the devs

The only downwards force is gravity, the lift is an “upwards force”, you can see that with the direction of the diagram
image

Its throwing thrust down pushing the aircraft up

Yeah, that is rather dumb, the harrier has a reputation for defying conventional laws of aerodynamics

Spoiler

So wing loading and its induced drag are quantities we can just neglect? Because the vector of the vertical thrust component is close to the lift vector, meaning that deflecting the nozzle downward will also start to unload the wing.

Correct, but that’s not what he or i have been saying. At 45 deg both of the vectors will be 70% the length of the resultant thus be of equal length and have a 50/50 split. At 60 degrees one of the vectors will be 50% the length of the resultant and the other will be 86,6% the length of the resultant. The split at 60 degrees will be approximately 58/42 .

Do you see how “split” and “percent of the resultant” are two different things ?

This is correct.

Correct, that statement is wrong, there is no “other 50%” because that’s not how you calculate that, it’s not a+b. I also have not seen him claim this.

I’m starting to wonder if this is a language barrier thing.

Thrust is a reactive force, you “throw” air back which generate trust fowards
imagen_2026-04-19_224905948

Here you go if you have a right angle with equal sides and you lay it down and apply force where does that force go

@Necronomica
image_2026-04-19_224935213

it doesn’t end up like this

image_2026-04-19_225112219

its not, english is his first language

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no

image

notice how it dosent add up to 20k lbs

almost as if thats what @Necronomica has been saying

congratulations, at 45 degrees nozzle angle the two forces are equal

this is exactly what you have called @Necronomica a troll for

exactly what he has been saying

They are yes, but are they 50% of the total? no. they are about 70% of the total, both of them.

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making them equal

Anyway, back to watching this thread rather than taking part:

kermit-the-frog-sip

I dont have the energy at the moment

3 Likes

like even his doc has been saying that
image

thats what he has been saying

hello reading comprhension?