He does not say split equal, he says half of the initial. Two VERY different things.
This is literally what the chart shows. Why is it 10,000lbs at 60 degrees in the chart?
That’s exactly what I’m talking about, and it’s completely missing from FeetPics calculations.
yes it is
COS(45 degrees) = .707
so are you telling me a 45 degree nozzle position has a 70 % offset in 1 direction? (of the aircrafts vertical and horizontal planes)
.707*28,000= 19,796 lbs force 1 way
and 8,204 in the other
at 45 degrees of nozzle angle
sure…
A 45 degree offset produces a thrust vector 0.707 timers that of the total thrust.
the horizontal will be 70% of the total and the vertical will also be 70% of the total.
It’s quite literally the reason that bridges look like this:
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great buddy you are a troll.
Vectoring the nozzle to 45 degrees results in a 50/50 split of power downwards and horizontally
a 12 year old could figure that out.
Nope doesn’t exist the other 50 percent is magical
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This is what he said, which is correct, that vertical portion is normal to the aircraft “trust line”
It was always considered a bit of a niche tactic IRL, though very valuable when applied correctly.
Though it is a real shame in-game it does genuinely nothing. especially the braking stop
Marketing lies
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And that’s why 12 year olds doesn’t design bridges.
at 45 degrees the vectors will be of equal length, they will not be half of the resultant each.
I’m giving up here, I’ve studied this exact thing and done complex multidimensional matrix calculations for structural engineering. I’m not trolling, I’m not stupid. I’m very much right here and at this point i’ll assume that it’s you who are trolling.
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Probably more like dev lazyness.
way too much effort to model proper engine temps or half decent damage models for all aircraft. Let alone vectored thrust for a handful. especially as it wont benefit soviet aircraft much
Exactly. And where is the aircraft’s lift vector directed? You see what I’m getting at?
I mean it kinda does something, it has save me quite a few times from eating the ground as it is an instant extra lift
Great I literally design/build things were calculations of force are needed.
I don’t know how much more simple I could literally put this for you.
A 60 degrees nozzle angle does not equate to a 50/50 split in the total power output acting on both the horizontal and vertical vectors
a 45 degree nozzle angle does…
He said before that at 60 degrees of nozzle 50% of the power would be applied horizontally so naturally the other 50 is vertical. That’s just wrong.
Yeah, it does reduce… increase? (Been a long day, semantics elude me tonight) stall speed, which can be very handy, but that is about it
To it is added to the lift of the aircraft, but you esencially reduce the foward thrust of the plane, his point is about this foward motion
I meant that the guy just pulled two parameters out of context and started comparing them with other aircraft without thrust vectoring. I’m curious how, using that logic, he would explain how the Harrier manages to perform a short takeoff at all.
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