An Aircraft with adequate sustained turn performance, the ability to rapidly decelerate to its best cornering velocity, and the ability to maintain controlled flight right down to very low airspeed and point the nose virtually anywhere relatively quickly. Its also impossible to lock this aircraft with a heat seeking missile during a high aspect pass, as the wing is hiding the jet exhaust and the front nozzles are cooling the turbine exhaust nozzles.
You can disagree with me all you like about what is considered important aspects, would be funny to see you disagree with what the professionals are saying.
The Sea Harrier is a brilliant combination of almost all the good parts of a fighter aircraft.
I used the correct one. The function to calculate horizontal thrust is the same one in the document. Once again you are looking and misunderstanding it. You can run the same function for the other angles and it will give you the same output. This is basic math and you have failed to comprehend it.
You claim 60 degrees of nozzle angle is 50/50 here it can be seen that 10,000 lbs is the Horizontal thrust component and 17,300 is the lift thrust component.
That’s a total thrust of 27,300 lbs meaning that 36.6% of the total thrust remains aft while 63.3% of the total thrust is vectored downward.
So quite literally your baseline value of 50/50 for 60 degrees of Oj is incorrect
I warned you about this ages ago, I told you, you can not apply basic aerodynamic principles to an aircraft that more often then not does not abide by basic aerodynamic principles.
Here you are now, doubling down on somethings that’s just obviously wrong. You tried to apply basic trigonometry for whatever reason to what would need to be advanced vectored jet propulsion mathematics.
Hey man, at least when I mistranslated the Flanker document I owned up to that and educated myself on that aircraft.
You’re misreading him. one thrust vector being 50% of the gross does not automatically mean that the other remaining thrust vector is also 50% because that’s not how trigonometry works.
Vectors have magnitude and direction and can work together to create resultants.
so naturally if you are going to have a vertical vector and a horizontal vector there is a resultant vector that comes from the relationship between the vertical and horizontal. The resultant force will change depending on the angle that these vectors meet. As well as how much more magnitude one has over the other.
Simply plugging in the COS(60 degrees) is not going to result in the correct answer for this case
