Reinforcement like on Su-27SK might be a thing. But Su-27SM is modifiocation of old Su-27S/P frames.
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This is the kind of detail in Soviet/RuF fighters I love from GJ.
The SM series had their elevator vortex generators (by intakes) removed does anyone know why?
Was the Flankers losing too much speed in a rate? So, they ditched the vortex generators for better speed retention since flying in max alpha was not needed outside of a knife fight? Will this be reflected in the model?
I am very certain this would decrease drag & increase the flankers energy retention, especially in turn rate. However it would lower the flankers stall point in angles of attack beyond lift. Btw those specific generators do nothing for the aircraft until it’s in max pitch where the top of the elevators can catch the destabilized airflow behind it. They produce undesired drag in every other flight regime otherwise.
Sukhoi must have decided that after evaluation of modern combat trends of the 21st century that excessive supermaneuverability is not essential over the aircraft’s ability to maintain energy. Therefore they removed the vortex generators.
They could have been planning to equip them with thrust vectoring which would not need the vortex’s generators too. I don’t think the modern flankers with tvc have the elevator vortex generators either.
This is all totally my theory, if anyone has anything on it please share. I love this kind of stuff.
What is the highest AoA of Su 27 at 1g stall ?
Multiplication is inversely proportional to division.And if I multiply by a linear coefficient A(k), then I must divide by a linear coefficient
Before Mach 0.9
the coefficient is static as.Then it is linear
Oswald static=0.751 for Su-27
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Not too sure.
The first iteration of the Flanker was already at 120° before the point of stall. At stall would be much higher. This analysis of Pugahchev’s demonstration at the 1989 Paris airshows states that there was no tendency for the aircraft to roll or departure at 100-120°indicating the aircraft was not near its stall point.
Proof the Mig-29 is supermaneuverable but GJ is playing games. Making up excuses about flight controls etc. This is why I want the R-27ER removed from it. To force them to do something about the FM.
The literal director of Центра́льный аэрогидродинами́ческий институ́т, ЦАГИ states the Mig-29 is capable. Western sources do too.
But the graph in the picture is not linear
And what is he like?
y=kx+b
The individual components are smaller and lighter, but the designers and engineers don’t like wasted space. So they add more trinkets and doodats which needs more wiring and more complex installations which usually always means the end result is the plane gains a lot of weight.
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The Mig-29 is vastly lighter, with a substantial higher thrust to weight.
The Mig-29 is vastly more simplified than the Flanker. Even its brakes are actually pneumatic… there is nothing complex about the Mig-29 & this was a major selling point of Mikoyan to export clients.
“Trinkets & doodats” is a theory not in line with any truth. Appreciate it, though.
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Because the MiG-29 had different requirements.By the time of deployment, preparation, maintenance and costs
The R-27R & ER is an outdated weapon system but the T & especially the ET are very advanced. Su-35s use the ET’s still.
Thank you so much, bit It is not 1G stal condition, it is rapid nose up maneuver - overshoot AoA in very small time - for very experinced pilots.
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Regardless of it still is very capable of hitting 90 degrees angles of attack. It cannot come near it in game with any Mig-29 variant flown min fuel with zero weapons in full real controls. That is definitely not correct.
Yeah, that why I said its definitely capable of over 120 since that is the degree before any sign of stall. That is why I highlighted that particular airshow because there is no actual true example of set degree at stall.
I provided what evidence is available for you to determine what you think it may be at stall. Definitely over 120.
Perhaps if the onset of AoA is at 1G, the stall will occur much sooner.
Ok, let’s suppose A(x) can be written as kx+b. Let’s first try to fit it. First, at Mach = 0, i.e. at x = 0
we have 0.21 = A(0) = k\cdot 0 + b = b, so we have b = 0.21.
Next. at x = 0.5 we have 0.21 = A(0.5) = k\cdot 0.5 + 0.21, meaning k = 0.
Seems like we have found our k and b, let’s check if it works somewhere else. Say, x = 1.5
A(1.5) = 0\cdot 1.5 + 0.21 = 0.21 \neq 0.37.5.
What??
Oh no, what a disaster, it does not match.
I wonder whyyyyyyy.
OH OH OH, I know, I KNOW. Could it maybe be because it is NOT A GOD DAMN STRAIGHT LINE???
For me, lose R-27R & R-27T from Su-27SM
Su-27SM3, Su-30SM, Su-30SM2 and Su-35S not armed R-27R & R-27T