Are You saying there is no difference between the average of the igla (~10g) and the average of the stinger/mistral (~25g)?
The stinger is clearly stated in primary and secondary sources to have an average pull of 22g (not 25, as the mistral)
The igla has a maximum pull of 16g
Mind if you refrain from calling me names? I can’t say I appreciate it
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Send me a sources that shows an average of 22g.
Send me the sources that the igla can pull 16g
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We have an average and a formula. However, that person is lying and saying that the maximum stinger overload is the average
Ok. Igla’s formula is correct. Yes. But the way this missile works is very different from Stinger or Mistral. You cannot use the same formula. For example: it doesn’t use PID for guidance. The rolling, rolling speed and such can also make big differences, it’s not just the aerodynamic surface.
So get a heavy fighter from WW2 and a modern jet, so that both of them have the same „wing surface”. Do you seriously think they will behave the same and there aren’t any other variables that might affect their performance? Seriously?
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You don’t know if the igla can physically pull 16gs and we already know that. Mathematics on being able don’t prove its physically able. And you dont know if the average on the mistral and stinger is 63% it could be more, it could be less. But we dont know if it is 63% because they are rolling systems and this formula doesnt apply to them
What primary source? I haven’t seen anypne show a single source that states 16G.
And that “formula” is already defective, as it was made based on igla with a different guidance system than stinger and mistral.
It doesn’t matter.
If we give igla according to the formula, we get 16g. What’s the difference
And Gaijin themselves says in the post they have the sources for higher Stinger and Mistral pull. They will just not use them because „the Igla looks similar and it can’t, so they can’t either”.
It’s the „base VW Golf and VW Golf GTI have the same shape and size ergo they have the same acceleration”.
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If the source has an average g. That’s enough to calculate the maximum.
If they write max g, igla will have 16 and nothing will change. Stinger will be better in the same ratio
With what formula? The one they got from igla?
NO IT ISN’T
Yeah, the formula on igla gives us a maximum of 16 from her average of 10.2.
Can’t you even do math?
You do realize I’m applying the formula for igla to herself? 10.2 avg - 16 max.
Yeah he can. Can you provide source that the igla can physically do 16g? Any papers, brochures, secondary sources? Anything?
If her average is 10.2, the formula says the maximum is 16
That “formula” isn’t a primary source lmfao.
Again, 5th time, can you provide ANY source that clearly says the 9m39 igla can physically do 16g maximum overload from any primary or secondary source?
That’s what it is, since it was obtained from igla documents