BAe Sea Harrier - Technical data and discussion

Do you realize that the vectors of these forces are almost aligned?

I definitely didn’t understand anything here.

brother

Yes, the lift is also bigger, what’s so hard to understand there?

It doesn’t, and no one has said this. the lift will be 86.6% of the input and the forward will be 50% of the input.

lift bigger, horizontal still 50% of input.

If you have the nozzles at 60 degrees down relative to 90 degrees

is the harrier going to accelerate harder upwards or forwards

Up.

if total is 20k.

Thrust up will be 20,000 * 0.866 = 17,320 pounds of force.

Thrust forward will be 20,000 * 0.5 = 10,000 pounds of force. (HALF OF INPUT)

Thrust forward is half of input. Thrust up is still a lot bigger than thrust forward.

great that is the only correct answer for this application.

horizontal is still half though.

That’s what I’ve been trying to tell you for the last hour

if that was the case it would accelerate equal parts forward and up

iirc this has been going on for 8 days now…

WRONG

like it cant be simpler than looking at this picture
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Yep… unfortunately, Gaijin hasnt even fixed the little stuff yet, so will probably go on for a while longer yet

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As soon as falcon 5 drops my Shar im out.

NO!!!

They are not equal. its half → OF INPUT ← not one half of the component two vectors.

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28,000 total

he said 50% of that is vectoring horizontally backwards

vectors meet at 90 degrees were is the other 50% going

It doesn’t exist, you can’t calculate it like that. Whenm using angles the two results are not linearly additive or subtractive.

28k total at 60 deg will give you one horizontal vector at 28,000 * 0.5 = 14,000 and the vertical vector at 28,000 * 0.866 = 24,248

cope feetpics stan

there is no logical explanation for you

if you were a harrier pilot you’d accelerate straight up thinking you were going to accelerate forwards.

go take a math course

or ask your math teacher

says the guy who cant even calculate SEP

thats physics btw not math
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