Amusing Graphic

shot 2025.10.07 06.26.39

A funny thing happened on my way through Golden Quarry in my French M55, when I noticed my .50 BMG ammunition had hexagonal rims. In what alternate universe had I dropped into?
Humor aside, has anyone else noticed this anomaly? No big deal, in no way a game breaker or even a complaint, I’m just curious.

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This has been around for years AFAIK bro.

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Also what graphics are you playing on?

LOL I’d have to look at my PC stats, I might do that tomorrow, it’s been a very long day! As for this being around for years, I’ve only been playing this game for about two years now, so I’m not a long-term player. Cheers!

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I’ve been playing for 5. Cheers! And yeah idk it might be your settings or gaijin just doesn’t care to fix it. I swear I’ve seen the hexagonal rims when playing on my PS4. Anyways, goodnight soldier. Let’s both get some good rest.

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this is normal

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Squared ammo hurt lots more due to more energy being dumped into a larger surface area.

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Always been like this

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My brother in dust mother, this is not math or science class.
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A low rez one.

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Literally unplayable. God forbid developers reducing polygons of small assets to conservate some power in poor John’s machine.

https://docs.blender.org/manual/en/latest/modeling/modifiers/generate/decimate.html

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Project wingman reference?

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Everything below max is not playable!

Indeed.

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Shut it.
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@cluckcluck1111-psn

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Prove: .50 BMG Round > Low resolution destitution institution de-evolution Confucian hexagonal round

Given: Diameter of .50 BMG round is 0.510 inches. All six vertices of the hexagon lie on the circle, all sides and angles of the hexagon are equal.


Divide the hexagon into six equilateral triangles by drawing lines from the center of the circle to each vertex

  • Each triangle has two sides that are radii of the circle.
  • The angle at the center of the circle for each triangle is 60° (360/60 = 60)
  • Results in a triangle with two equal sides (radiuses) and a 60° angle between them.

Interior angles of a hexagon are 120°, when bisected by radiuses each angle become 60°. Since all interior angles of the triangle are congruent, all sides are congruent (Reasoning: definition of an equilateral triangle) Therefore, the third side (the side of the hexagon) must also be equal to the radius.

Length of each side of hexagon = 0.255


Area of hexagon

Area = (3(√3) / 2) x (0.255)^2

Area ≈ 0.167 inches²


Area of .50 BMG round

area = 𝜋 (.255) ^2

area = 0.204 inches²


0.204 inches² > 0.167 inches²

.50 BMG round > Low resolution destitution institution de-evolution Confucian hexagonal round

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nah we need our beautiful visuals to enjoy flying through the sky with a Mig-29 or driving through the mud with Tiger

I’m gonna nail you with an AIM-9B. The fabled cluckcluck1111 always carries.

Dude you use ai or smth 😭
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I’m legit gonna cry if you actually took your time and did that yourself.